Question:
If the total absorption of a hall is doubled, the reverberation time will
If the total absorption of a hall is doubled, the reverberation time will
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Reverberation time $T \propto 1/A$. More absorption means sound dies out faster.
Updated On: Jul 4, 2026
- Double
- Become half
- Remain same
- Become four times
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The Correct Option is B
Solution and Explanation
Step 1: Concept
According to Sabine's formula, reverberation time $T = \frac{0.161V}{A}$, where $V$ is volume and $A$ is total absorption.
Step 2: Meaning
This formula shows that reverberation time $T$ is inversely proportional to total absorption $A$.
Step 3: Analysis
If $A$ is doubled ($A_{new} = 2A$), then $T_{new} = \frac{0.161V}{2A} = \frac{T}{2}$.
Step 4: Conclusion
Therefore, the reverberation time will become half. Final Answer: (B)
According to Sabine's formula, reverberation time $T = \frac{0.161V}{A}$, where $V$ is volume and $A$ is total absorption.
Step 2: Meaning
This formula shows that reverberation time $T$ is inversely proportional to total absorption $A$.
Step 3: Analysis
If $A$ is doubled ($A_{new} = 2A$), then $T_{new} = \frac{0.161V}{2A} = \frac{T}{2}$.
Step 4: Conclusion
Therefore, the reverberation time will become half. Final Answer: (B)
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