Question:

If the mean deviation of a distribution is 20.20, the standard deviation of this distribution is :

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Use the empirical relation QD : MD : SD = 10 : 12 : 15, so SD = (5/4) x MD.
Updated On: Jul 4, 2026
  • 15.15
  • 25.25
  • 30.39
  • None of these
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The Correct Option is B

Solution and Explanation

Step 1: Recall the standard empirical relationship among the three common measures of dispersion, namely quartile deviation (QD), mean deviation (MD) and standard deviation (SD), when the distribution is reasonably symmetric (moderately normal).\[QD : MD : SD = 10 : 12 : 15\]
Step 2: From this ratio, mean deviation and standard deviation are related as\[MD = \frac{12}{15} SD = \frac{4}{5} SD\]
Step 3: Rearrange to express SD in terms of MD.\[SD = \frac{5}{4} MD\]
Step 4: Substitute the given mean deviation \(MD = 20.20\).\[SD = \frac{5}{4} \times 20.20 = 1.25 \times 20.20 = 25.25\]
Step 5: So the standard deviation of the distribution is 25.25, which matches option (B).
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