Step 1: The standard deviation of \(X\) is 5, so the variance of \(X\) is \[\text{Var}(X) = 5^2 = 25\]
Step 2: Use the property that for constants \(a\) and \(b\), \[\text{Var}(aX + b) = a^2 \, \text{Var}(X)\] Here \(Y = 2X - 5\), so \(a = 2\) and \(b = -5\). The additive constant \(b\) does not affect variance.
Step 3: Substitute the values: \[\text{Var}(Y) = 2^2 \times 25 = 4 \times 25 = 100\]
So the variance of \(Y\) is 100, which is option (B). (Note: the mean of \(X\), which is 3, is not needed for this calculation since it only affects the mean of \(Y\), not its variance.)