According to Hardy-Weinberg equilibrium, the genotype frequency of Aa is given by \( 2pq \), where \( p = 0.6 \) (frequency of A) and \( q = 1 - p = 0.4 \).
\[ 2pq = 2 \times 0.6 \times 0.4 = 0.48 \] The correct genotype frequency of Aa is actually \( 0.48 \)