Question

If a centre tap transformer is used with two p-n junction diodes for full wave rectification then output voltage of rectifier with respect to each diode is (secondary voltage of transformer $= V_s$ )

• A. $2 V_s$
• B. $\left( \frac{2}{3} \right) V_s$
• C. $\left( \frac{1}{2} \right) V_s$
• D. $\left( \frac{3}{2} \right) V_s$

Hint:

A centre tap divides the secondary winding into two equal halves, so each side gives half of the total secondary voltage.

Answer 1

The Correct Option is C

Concept:
In a centre-tapped transformer, the total secondary voltage is split equally across the two halves. ip

Step 1: Interpret the centre-tapped transformer.
If total secondary voltage is: \[ V_s \] then voltage across each half of the secondary winding is: \[ \frac{V_s}{2} \] ip

Step 2: Relate it to each diode.
Each diode in a two-diode full wave rectifier is connected to one half of the secondary winding. So output with respect to each diode corresponds to: \[ \frac{V_s}{2} \] ip Hence, the correct answer is:
\[ \boxed{(C)\ \frac{V_s}{2}} \]