(i) It is known that A=(A')'
Therefore, we have:
A= \(\begin{bmatrix} 3 & -1 & 0 \\ 4 & 2 & 1 \end{bmatrix}\)
B'= \(\begin{bmatrix} -1 & 1 \\ 2 & 2 \\ 1 &3 \end{bmatrix}\)
\(A+B\) = \(\begin{bmatrix} 3 & -1 & 0 \\ 4 & 2 & 1 \end{bmatrix}\) + \(\begin{bmatrix} -1 & 2 & 1 \\ 1 &2 & 3\end{bmatrix}\)= \(\begin{bmatrix} 2 & 1 & 1 \\ 5 & 4 & 4 \end{bmatrix}\)
\(\therefore (A+B)'=\) \(\begin{bmatrix} 2 & 5 \\ 1 & 4 \\ 1 &4 \end{bmatrix}\)
\(A'+B'=\) \(\begin{bmatrix} 3 & 4 \\ -1 & 2 \\ 0 &1 \end{bmatrix}\)+ \(\begin{bmatrix} -1 & 1 \\ 2 & 2 \\ 1 &3 \end{bmatrix}\)= \(\begin{bmatrix} 2 & 5 \\ 1 & 4 \\ 1 &4 \end{bmatrix}\)
Thus, we verified that:(A+B)'=A'+B'
(ii) \(A-B\)= \(\begin{bmatrix} 3 & -1 & 0 \\ 4 & 2 & 1 \end{bmatrix}\)- \(\begin{bmatrix} -1 & 2 & 1 \\ 1 &2 & 3\end{bmatrix}\) = \(\begin{bmatrix} 4 & -3 & -1 \\ 3 &0 & -2\end{bmatrix}\)
so\( (A-B)'\) = \(\begin{bmatrix} -4 & 3 \\ -3 & 0 \\ -1 &-2 \end{bmatrix}\)
A'-B'= \(\begin{bmatrix} 3 & 4 \\ -1 & 2 \\ 0 &1 \end{bmatrix}\)- \(\begin{bmatrix} -1 & 1 \\ 2 & 2 \\ 1 &3 \end{bmatrix}\)= \(\begin{bmatrix} -4 & 3 \\ -3 & 0 \\ -1 &-2 \end{bmatrix}\)
Hence we verified that: \((A-B)'=A'-B'\)
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
In the matrix A= \(\begin{bmatrix} 2 & 5 & 19&-7 \\ 35 & -2 & \frac{5}{2}&12 \\ \sqrt3 & 1 & -5&17 \end{bmatrix}\),write:
I. The order of the matrix
II. The number of elements
III. Write the elements a13, a21, a33, a24, a23
If a matrix has 24 elements, what are the possible order it can have? What, if it has 13 elements?
If a matrix has 18 elements, what are the possible orders it can have? What, if it has 5 elements?
Construct a 3×4 matrix, whose elements are given by
I. \(a_{ij}=\frac{1}{2}\mid -3i+j\mid\)
II. \(a_{ij}=2i-j\)
Find the value of x, y, and z from the following equation:
I.\(\begin{bmatrix} 4&3&\\x&5\end{bmatrix}=\begin{bmatrix}y&z\\1&5\end{bmatrix}\)
II. \(\begin{bmatrix}x+y&2\\5+z&xy\end{bmatrix}=\begin{bmatrix}6&2\\5&8\end{bmatrix}\)
III. \(\begin{bmatrix}x+y+z\\x+z\\y+z\end{bmatrix}=\begin{bmatrix}9\\5\\7\end{bmatrix}\)
The matrix acquired by interchanging the rows and columns of the parent matrix is called the Transpose matrix. The transpose matrix is also defined as - “A Matrix which is formed by transposing all the rows of a given matrix into columns and vice-versa.”
The transpose matrix of A is represented by A’. It can be better understood by the given example:


Now, in Matrix A, the number of rows was 4 and the number of columns was 3 but, on taking the transpose of A we acquired A’ having 3 rows and 4 columns. Consequently, the vertical Matrix gets converted into Horizontal Matrix.
Hence, we can say if the matrix before transposing was a vertical matrix, it will be transposed to a horizontal matrix and vice-versa.
Read More: Transpose of a Matrix