If A=\(\begin{bmatrix}-1&2&3\\5&7&9\\-2&1&1\end{bmatrix}\)and B=\(\begin{bmatrix}-4&1&-5\\1&2&0\\1&3&1\end{bmatrix}\),then verify that
(i)(A+B)'=A'+B'
(ii)(A-B)'=A'-B'
We have: A'=\(\begin{bmatrix}-1&5&-2\\2&7&1\\3&9&1\end{bmatrix}\),B'=\(\begin{bmatrix}-4&1&1\\1&2&3\\-5&0&1\end{bmatrix}\)
(i)A+B= \(\begin{bmatrix}-1&2&3\\5&7&9\\-2&1&1\end{bmatrix}\)+\(\begin{bmatrix}-4&1&-5\\1&2&0\\1&3&1\end{bmatrix}\)
=\(\begin{bmatrix}-5&3&-2\\6&9&9\\1&4&2\end{bmatrix}\)
therefore (A+B)'=\(\begin{bmatrix}-5&6&-1\\3&9&4\\-2&9&2\end{bmatrix}\)
A'+B'=\(\begin{bmatrix}-1&5&-2\\2&7&1\\3&9&1\end{bmatrix}\)+\(\begin{bmatrix}-4&1&1\\1&2&3\\-5&0&1\end{bmatrix}\)
Hence we verified that (A+B)'=A'+B'
(ii)A-B=\(\begin{bmatrix}-1&2&3\\5&7&9\\-2&1&1\end{bmatrix}\)-\(\begin{bmatrix}-4&1&-5\\1&2&0\\1&3&1\end{bmatrix}\)
=\(\begin{bmatrix}3&1&8\\4&5&9\\-3&-2&0\end{bmatrix}\)
therefore (A-B)'=\(\begin{bmatrix}-3&4&-3\\1&5&-2\\8&9&0\end{bmatrix}\)
A'-B'=\(\begin{bmatrix}-1&5&-2\\2&7&1\\3&9&1\end{bmatrix}\)-\(\begin{bmatrix}-4&1&1\\1&2&3\\-5&0&1\end{bmatrix}\)
=\(\begin{bmatrix}-3&4&-3\\1&5&-2\\8&9&0\end{bmatrix}\)
Hence we verified that (A-B)'=A'-B'
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
In the matrix A= \(\begin{bmatrix} 2 & 5 & 19&-7 \\ 35 & -2 & \frac{5}{2}&12 \\ \sqrt3 & 1 & -5&17 \end{bmatrix}\),write:
I. The order of the matrix
II. The number of elements
III. Write the elements a13, a21, a33, a24, a23
If a matrix has 24 elements, what are the possible order it can have? What, if it has 13 elements?
If a matrix has 18 elements, what are the possible orders it can have? What, if it has 5 elements?
Construct a 3×4 matrix, whose elements are given by
I. \(a_{ij}=\frac{1}{2}\mid -3i+j\mid\)
II. \(a_{ij}=2i-j\)
Find the value of x, y, and z from the following equation:
I.\(\begin{bmatrix} 4&3&\\x&5\end{bmatrix}=\begin{bmatrix}y&z\\1&5\end{bmatrix}\)
II. \(\begin{bmatrix}x+y&2\\5+z&xy\end{bmatrix}=\begin{bmatrix}6&2\\5&8\end{bmatrix}\)
III. \(\begin{bmatrix}x+y+z\\x+z\\y+z\end{bmatrix}=\begin{bmatrix}9\\5\\7\end{bmatrix}\)
The matrix acquired by interchanging the rows and columns of the parent matrix is called the Transpose matrix. The transpose matrix is also defined as - “A Matrix which is formed by transposing all the rows of a given matrix into columns and vice-versa.”
The transpose matrix of A is represented by A’. It can be better understood by the given example:


Now, in Matrix A, the number of rows was 4 and the number of columns was 3 but, on taking the transpose of A we acquired A’ having 3 rows and 4 columns. Consequently, the vertical Matrix gets converted into Horizontal Matrix.
Hence, we can say if the matrix before transposing was a vertical matrix, it will be transposed to a horizontal matrix and vice-versa.
Read More: Transpose of a Matrix