If A=\(\begin{bmatrix}-1&2&3\\5&7&9\\-2&1&1\end{bmatrix}\)and B=\(\begin{bmatrix}-4&1&-5\\1&2&0\\1&3&1\end{bmatrix}\),then verify that
(i)(A+B)'=A'+B'
(ii)(A-B)'=A'-B'
We have: A'=\(\begin{bmatrix}-1&5&-2\\2&7&1\\3&9&1\end{bmatrix}\),B'=\(\begin{bmatrix}-4&1&1\\1&2&3\\-5&0&1\end{bmatrix}\)
(i)A+B= \(\begin{bmatrix}-1&2&3\\5&7&9\\-2&1&1\end{bmatrix}\)+\(\begin{bmatrix}-4&1&-5\\1&2&0\\1&3&1\end{bmatrix}\)
=\(\begin{bmatrix}-5&3&-2\\6&9&9\\1&4&2\end{bmatrix}\)
therefore (A+B)'=\(\begin{bmatrix}-5&6&-1\\3&9&4\\-2&9&2\end{bmatrix}\)
A'+B'=\(\begin{bmatrix}-1&5&-2\\2&7&1\\3&9&1\end{bmatrix}\)+\(\begin{bmatrix}-4&1&1\\1&2&3\\-5&0&1\end{bmatrix}\)
Hence we verified that (A+B)'=A'+B'
(ii)A-B=\(\begin{bmatrix}-1&2&3\\5&7&9\\-2&1&1\end{bmatrix}\)-\(\begin{bmatrix}-4&1&-5\\1&2&0\\1&3&1\end{bmatrix}\)
=\(\begin{bmatrix}3&1&8\\4&5&9\\-3&-2&0\end{bmatrix}\)
therefore (A-B)'=\(\begin{bmatrix}-3&4&-3\\1&5&-2\\8&9&0\end{bmatrix}\)
A'-B'=\(\begin{bmatrix}-1&5&-2\\2&7&1\\3&9&1\end{bmatrix}\)-\(\begin{bmatrix}-4&1&1\\1&2&3\\-5&0&1\end{bmatrix}\)
=\(\begin{bmatrix}-3&4&-3\\1&5&-2\\8&9&0\end{bmatrix}\)
Hence we verified that (A-B)'=A'-B'
If A and B are two n times n non-singular matrices, then
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).
The matrix acquired by interchanging the rows and columns of the parent matrix is called the Transpose matrix. The transpose matrix is also defined as - “A Matrix which is formed by transposing all the rows of a given matrix into columns and vice-versa.”
The transpose matrix of A is represented by A’. It can be better understood by the given example:


Now, in Matrix A, the number of rows was 4 and the number of columns was 3 but, on taking the transpose of A we acquired A’ having 3 rows and 4 columns. Consequently, the vertical Matrix gets converted into Horizontal Matrix.
Hence, we can say if the matrix before transposing was a vertical matrix, it will be transposed to a horizontal matrix and vice-versa.
Read More: Transpose of a Matrix