Question:
If 10 percent of the current passes through a moving coil galvanometer of resistance 99 ohm. Then the shunt resistance will be:
If 10 percent of the current passes through a moving coil galvanometer of resistance 99 ohm. Then the shunt resistance will be:
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To calculate the shunt resistance, use the formula \( R_s = \frac{R}{n - 1} \).
Updated On: Apr 22, 2026
- 9.9 ohm
- 11 ohm
- 10 ohm
- 9 ohm
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The Correct Option is B
Solution and Explanation
Step 1: Use the formula for shunt resistance.
The shunt resistance \( R_s \) is given by: \[ R_s = \frac{R}{n - 1} \] where \( R \) is the resistance of the galvanometer and \( n \) is the factor by which the current is divided.
Step 2: Calculate the shunt resistance.
Here, 10 percent of the current passes through the galvanometer, so \( n = 10 \). Substituting the values: \[ R_s = \frac{99}{10 - 1} = \frac{99}{9} = 11 \, \Omega \]
Step 3: Conclusion.
The shunt resistance is 11 ohm, which is option (2).
The shunt resistance \( R_s \) is given by: \[ R_s = \frac{R}{n - 1} \] where \( R \) is the resistance of the galvanometer and \( n \) is the factor by which the current is divided.
Step 2: Calculate the shunt resistance.
Here, 10 percent of the current passes through the galvanometer, so \( n = 10 \). Substituting the values: \[ R_s = \frac{99}{10 - 1} = \frac{99}{9} = 11 \, \Omega \]
Step 3: Conclusion.
The shunt resistance is 11 ohm, which is option (2).
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