Question:

Identify the temperature required for preparation of ethoxyethane from ethanol in the presence of \(\text{H}_{2}\text{SO}_{4}\).

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Excess ethanol with conc. H2SO4 at 413 K gives ether, while 443 K gives ethene.
Updated On: Nov 12, 2026
  • \(113K\)
  • \(443K\)
  • \(413K\)
  • \(213K\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
Ethanol with concentrated \(\text{H}_{2}\text{SO}_{4}\) gives different products at different temperatures.

Step 2: Temperature Effect
At \(443\ \text{K}\) the product is ethene (intramolecular dehydration).
At \(413\ \text{K}\) with excess alcohol, the product is ethoxyethane (intermolecular dehydration).

Step 3: Equation
\(2\text{C}_{2}\text{H}_{5}\text{OH}\xrightarrow{\text{H}_{2}\text{SO}_{4},\ 413\ \text{K}}\text{C}_{2}\text{H}_{5}\text{OC}_{2}\text{H}_{5}+\text{H}_{2}\text{O}\).

Final Answer:
The temperature is 413 K, option (C). \[ \boxed{\text{(C) }413K} \]
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