Step 1: Write the structure of the ether.
3–Chloropropyl ethyl ether has the structure:
\[
\text{CH}_3\text{CH}_2\text{O–CH}_2\text{CH}_2\text{CH}_2\text{Cl}
\]
Step 2: Select the parent chain.
The longer carbon chain is propane, so propane is taken as the parent hydrocarbon.
Step 3: Identify substituents and their positions.
An ethoxy group (\(-\text{OC}_2\text{H}_5\)) is attached at carbon 1, and a chloro group (\(-\text{Cl}\)) is attached at carbon 3.
Step 4: Apply IUPAC nomenclature rules.
Substituents are written in alphabetical order with appropriate locants, giving the name:
\[
\text{3–Chloro–1–ethoxypropane}
\]
Step 5: Conclusion.
Hence, the correct IUPAC name is 3–Chloro–1–ethoxypropane.