Question:
When methoxybenzene reacts with HI at room temperature the products formed are
When methoxybenzene reacts with HI at room temperature the products formed are
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In the reaction of methoxybenzene with HI, the methoxy group is replaced by iodine, forming iodomethane and phenol.
Updated On: Jan 26, 2026
- Iodomethane and Iodobenzene
- Iodomethane and Phenol
- Methanol and Iodobenzene
- Iodomethane and Benzene
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the reaction.
Methoxybenzene (anisole) reacts with hydroiodic acid (HI) in a nucleophilic substitution reaction. The methoxy group (-OCH\(_3\)) is electron-donating and activates the aromatic ring for substitution. The reaction leads to the formation of iodomethane (CH\(_3\)I) and phenol (C\(_6\)H\(_5\)OH).
Step 2: Analyzing the options.
(A) Iodomethane and Iodobenzene: This is incorrect. Iodobenzene is not formed in this reaction.
(B) Iodomethane and Phenol: This is correct. The reaction produces iodomethane and phenol.
(C) Methanol and Iodobenzene: This is incorrect. Methanol is not formed in this reaction.
(D) Iodomethane and Benzene: This is incorrect. Benzene is not formed in this reaction.
Step 3: Conclusion.
The correct answer is (B) Iodomethane and Phenol.
Methoxybenzene (anisole) reacts with hydroiodic acid (HI) in a nucleophilic substitution reaction. The methoxy group (-OCH\(_3\)) is electron-donating and activates the aromatic ring for substitution. The reaction leads to the formation of iodomethane (CH\(_3\)I) and phenol (C\(_6\)H\(_5\)OH).
Step 2: Analyzing the options.
(A) Iodomethane and Iodobenzene: This is incorrect. Iodobenzene is not formed in this reaction.
(B) Iodomethane and Phenol: This is correct. The reaction produces iodomethane and phenol.
(C) Methanol and Iodobenzene: This is incorrect. Methanol is not formed in this reaction.
(D) Iodomethane and Benzene: This is incorrect. Benzene is not formed in this reaction.
Step 3: Conclusion.
The correct answer is (B) Iodomethane and Phenol.
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