Question:
Identify the reagent used in the transformation of Ketone into semicarbazone.
Identify the reagent used in the transformation of Ketone into semicarbazone.
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Semicarbazide is NH2-NH-CONH2.
Updated On: Oct 1, 2026
- \(\text{NH}_2-\text{OH}\)
- \(\text{NH}_2-\text{NH}_2\)
- \(\text{NH}_2-\text{NH}-\text{CONH}_2\)
- \(\text{NH}_2-\text{NH}-\text{C}_6\text{H}_5\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Aldehydes and ketones react with ammonia derivatives \(\text{NH}_2\text{-Z}\) in a condensation reaction. Water is lost and a C=N compound forms. The name of the product depends on Z.
Step 2: Detailed Explanation:
\(\text{NH}_2\text{OH}\), hydroxylamine, gives an oxime. \(\text{NH}_2\text{NH}_2\), hydrazine, gives a hydrazone. \(\text{NH}_2\text{NH-CONH}_2\), semicarbazide, gives a semicarbazone. \(\text{NH}_2\text{NH-C}_6\text{H}_5\), phenylhydrazine, gives a phenylhydrazone.
Final Answer:
The reagent is semicarbazide, option (C). \[ \boxed{\text{NH}_2\text{-NH-CONH}_2} \]
Aldehydes and ketones react with ammonia derivatives \(\text{NH}_2\text{-Z}\) in a condensation reaction. Water is lost and a C=N compound forms. The name of the product depends on Z.
Step 2: Detailed Explanation:
\(\text{NH}_2\text{OH}\), hydroxylamine, gives an oxime. \(\text{NH}_2\text{NH}_2\), hydrazine, gives a hydrazone. \(\text{NH}_2\text{NH-CONH}_2\), semicarbazide, gives a semicarbazone. \(\text{NH}_2\text{NH-C}_6\text{H}_5\), phenylhydrazine, gives a phenylhydrazone.
Final Answer:
The reagent is semicarbazide, option (C). \[ \boxed{\text{NH}_2\text{-NH-CONH}_2} \]
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