Question:
Identify the product obtained when alkyl alkanoate is hydrolysed with dilute $\text{HCl}$.
Identify the product obtained when alkyl alkanoate is hydrolysed with dilute $\text{HCl}$.
Show Hint
Ester hydrolysis:
Ester + Water $\rightarrow$ Acid + Alcohol
Updated On: May 8, 2026
- Alkanol and Alkanoic acid
- Alkanal and Alkanone
- Alkanone and Alkanoic acid
- Alkanol and Alkanal
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Concept: Acidic hydrolysis of esters produces alcohol and carboxylic acid. \[ \text{RCOOR'} + \text{H}_2\text{O} \xrightarrow{\text{HCl}} \text{RCOOH} + \text{R'OH} \]
Step 1: Identify reactant.
Alkyl alkanoate = ester.
Step 2: Hydrolysis reaction.
Breaks ester bond forming:
• Alkanoic acid
• Alkanol
Step 3: Conclusion.
Products are alcohol and carboxylic acid. Final Answer: Option (A)
Was this answer helpful?
0
0
Top MHT CET Chemistry Questions
- The temperature of $32^{\circ}C$ is equivalent to
- The heat of formation of water is $ 260\, kJ $ . How much $ H_2O $ is decomposed by $ 130\, kJ $ of heat ?
- If a metal crystallises in bcc structure with edge length of unit cell $4.29 \times 10^{-8}\, cm$ the radius of metal atom is
- Which of the following oxides can act both as an oxidising agent as well as reducing agent ?
- "The mass and energy both are conserved in an isolated system", is the statement of
View More Questions
Top MHT CET Chemical Reactions of Aldehydes Ketones and Carboxylic Acids Questions
Top MHT CET Questions
- During r- DNA technology, which one of the following enzymes is used for cleaving DNA molecule ?
- In non uniform circular motion, the ratio of tangential to radial acceleration is (r = radius of circle, $v =$ speed of the particle, $\alpha =$ angular acceleration)
- The temperature of $32^{\circ}C$ is equivalent to
- The line $5x + y - 1 = 0$ coincides with one of the lines given by $5x^2 + xy - kx - 2y + 2 = 0 $ then the value of k is
- The heat of formation of water is $ 260\, kJ $ . How much $ H_2O $ is decomposed by $ 130\, kJ $ of heat ?
View More Questions