Question:
Identify the products of following reaction.
\[ \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOC}_2 \mathrm{H}_5 \xrightarrow[\text { dil H}_2 \mathrm{SO}_4]{\Delta} \text { Products } \]
Identify the products of following reaction.
\[ \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOC}_2 \mathrm{H}_5 \xrightarrow[\text { dil H}_2 \mathrm{SO}_4]{\Delta} \text { Products } \]
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Hydrolysis of an ester with a dilute acid gives the parent carboxylic acid and the alcohol.
Updated On: Nov 13, 2026
\(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{OH}+\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH}\)
\(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{OH}+\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{COOH}\)
\(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{COOH}+\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH}\)
\(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{COOH}+\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{COOH}\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
Ester hydrolysis in dilute acid splits \(\text{R-COO-R'}\) into \(\text{R-COOH}\) and \(\text{R'-OH}\).
Step 2: Apply to the ester
In \(\text{C}_6\text{H}_5\text{COOC}_2\text{H}_5\), the acyl part is \(\text{C}_6\text{H}_5\text{CO-}\) and the alkyl part is \(\text{C}_2\text{H}_5\).
Step 3: Products
\(\text{C}_6\text{H}_5\text{COOC}_2\text{H}_5 + \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_5\text{COOH} + \text{C}_2\text{H}_5\text{OH}\)
This gives benzoic acid and ethanol.
Final Answer:
The ester gives benzoic acid and ethanol. \[ \boxed{\text{(C) }\text{C}_{6}\text{H}_{5}\text{COOH}+\text{C}_{2}\text{H}_{5}\text{OH}} \]
Ester hydrolysis in dilute acid splits \(\text{R-COO-R'}\) into \(\text{R-COOH}\) and \(\text{R'-OH}\).
Step 2: Apply to the ester
In \(\text{C}_6\text{H}_5\text{COOC}_2\text{H}_5\), the acyl part is \(\text{C}_6\text{H}_5\text{CO-}\) and the alkyl part is \(\text{C}_2\text{H}_5\).
Step 3: Products
\(\text{C}_6\text{H}_5\text{COOC}_2\text{H}_5 + \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_5\text{COOH} + \text{C}_2\text{H}_5\text{OH}\)
This gives benzoic acid and ethanol.
Final Answer:
The ester gives benzoic acid and ethanol. \[ \boxed{\text{(C) }\text{C}_{6}\text{H}_{5}\text{COOH}+\text{C}_{2}\text{H}_{5}\text{OH}} \]
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