Question:
Identify the product \(Z\) formed in the given sequence of reactions
Identify the product \(Z\) formed in the given sequence of reactions
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Gattermann-Koch reaction introduces the formyl group (-CHO) into benzene ring to form benzaldehyde.
Updated On: Jul 29, 2026
- Fig 1 (Chlorobenzene)
- Fig 2 (Benzaldehyde)
- Fig 3 (Benzoyl chloride)
- Fig 4 (Benzyl chloride)
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The Correct Option is B
Solution and Explanation
Step 1: Hydrolysis of benzene diazonium chloride
Benzene diazonium chloride on hydrolysis with water gives phenol:
\[
C_6H_5N_2^+Cl^- + H_2O \rightarrow C_6H_5OH + N_2 + HCl
\]
So,
\[
X=\text{Phenol}
\]
Step 2: Reduction of phenol with Zn dust Phenol on heating with zinc dust gets reduced to benzene: \[ C_6H_5OH + Zn \rightarrow C_6H_6 + ZnO \] So, \[ Y=\text{Benzene} \]
Step 3: Gattermann-Koch reaction Benzene reacts with: \[ CO+HCl \] in presence of: \[ \text{Anhydrous } AlCl_3 \] to form benzaldehyde. \[ C_6H_6 \rightarrow C_6H_5CHO \] So, \[ Z=\text{Benzaldehyde} \] \[ \boxed{Z=\text{Benzaldehyde}} \] Therefore, the correct answer is: \[ \boxed{(B)} \]
Step 2: Reduction of phenol with Zn dust Phenol on heating with zinc dust gets reduced to benzene: \[ C_6H_5OH + Zn \rightarrow C_6H_6 + ZnO \] So, \[ Y=\text{Benzene} \]
Step 3: Gattermann-Koch reaction Benzene reacts with: \[ CO+HCl \] in presence of: \[ \text{Anhydrous } AlCl_3 \] to form benzaldehyde. \[ C_6H_6 \rightarrow C_6H_5CHO \] So, \[ Z=\text{Benzaldehyde} \] \[ \boxed{Z=\text{Benzaldehyde}} \] Therefore, the correct answer is: \[ \boxed{(B)} \]
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