Step 1: Reaction of cyclopentyl chloride with ethanolic KCN.
Alkyl halides react with KCN through nucleophilic substitution.
The cyanide ion attacks through the carbon atom and forms a nitrile:
\[
\text{Cyclopentyl chloride}
\rightarrow
\text{Cyclopentyl cyanide}
\]
\[
C_5H_9Cl + KCN
\rightarrow
C_5H_9CN + KCl
\]
Step 2: Reduction of nitrile.
Nitriles on reduction with sodium amalgam in ethanol are converted into primary amines.
The nitrile group
\[
-CN
\]
is reduced to
\[
-CH_2NH_2
\]
Therefore,
\[
C_5H_9CN
\rightarrow
C_5H_9CH_2NH_2
\]
Step 3: Identify the product.
The product formed is
Cyclopentylmethylamine
which corresponds to a cyclopentane ring attached to
\[
-CH_2NH_2
\]
This is represented by option (2).
Step 4: Final conclusion.
Therefore, the final product is
\[
\boxed{\text{Cyclopentylmethylamine}}
\]
Hence, the correct option is
\[
\boxed{(2)}
\]