Question:
Identify the product formed in the following reaction: $CH_{3}CH_{2}MgBr \xrightarrow[ii)~dil.~HCl]{i)~Dry~ice/dry~ether} Product$
Identify the product formed in the following reaction: $CH_{3}CH_{2}MgBr \xrightarrow[ii)~dil.~HCl]{i)~Dry~ice/dry~ether} Product$
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Reaction with $CO_2$ increases the carbon chain length by one.
Updated On: Jun 19, 2026
- Ethanoic acid
- Propanoic acid
- 2-Methylpropanoic acid
- Butanoic acid
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Grignard reagent ($RMgX$) reacts with dry ice ($CO_2$) to form a carboxylic acid salt.
Step 2: Analysis
- $CH_3CH_2MgBr + CO_2 \rightarrow CH_3CH_2COOMgBr$ - Hydrolysis: $CH_3CH_2COOMgBr \xrightarrow{H_3O^+} CH_3CH_2COOH + Mg(OH)Br$
Step 3: Conclusion
The product is Propanoic acid ($C_3$ acid). Final Answer: (B)
Grignard reagent ($RMgX$) reacts with dry ice ($CO_2$) to form a carboxylic acid salt.
Step 2: Analysis
- $CH_3CH_2MgBr + CO_2 \rightarrow CH_3CH_2COOMgBr$ - Hydrolysis: $CH_3CH_2COOMgBr \xrightarrow{H_3O^+} CH_3CH_2COOH + Mg(OH)Br$
Step 3: Conclusion
The product is Propanoic acid ($C_3$ acid). Final Answer: (B)
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