Question:
Identify the product 'A' in the following reaction: Anisole $\xrightarrow[398~K]{HI}$ A + Iodomethane}
Identify the product 'A' in the following reaction: Anisole $\xrightarrow[398~K]{HI}$ A + Iodomethane}
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Aryl-Oxygen bonds are stronger than Alkyl-Oxygen bonds due to resonance.
Updated On: Jun 19, 2026
- Aniline
- Iodobenzene
- Benzenol
- Benzene
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The Correct Option is C
Solution and Explanation
Step 1: Concept
Cleavage of alkyl aryl ethers by hydrogen halides ($HX$).
Step 2: Analysis
- Anisole is Methoxybenzene ($C_{6}H_{5}OCH_{3}$). - In the reaction with $HI$, the bond between $O-CH_{3}$ breaks because the $Ar-O$ bond has partial double bond character. - Products: $C_{6}H_{5}OH$ (Phenol or Benzenol) and $CH_{3}I$ (Iodomethane).
Step 3: Conclusion
Hence, product 'A' is Benzenol (Phenol). Final Answer: (C)
Cleavage of alkyl aryl ethers by hydrogen halides ($HX$).
Step 2: Analysis
- Anisole is Methoxybenzene ($C_{6}H_{5}OCH_{3}$). - In the reaction with $HI$, the bond between $O-CH_{3}$ breaks because the $Ar-O$ bond has partial double bond character. - Products: $C_{6}H_{5}OH$ (Phenol or Benzenol) and $CH_{3}I$ (Iodomethane).
Step 3: Conclusion
Hence, product 'A' is Benzenol (Phenol). Final Answer: (C)
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