Question:
Identify the molecules which have sp-hybridized carbon(s) from the list given under:
I. Ethane nitrile
II. Buta-1,3-diene
III. Propa-1,2-diene
IV. Ethyne
V. Benzene
Identify the molecules which have sp-hybridized carbon(s) from the list given under:
I. Ethane nitrile
II. Buta-1,3-diene
III. Propa-1,2-diene
IV. Ethyne
V. Benzene
I. Ethane nitrile
II. Buta-1,3-diene
III. Propa-1,2-diene
IV. Ethyne
V. Benzene
Show Hint
sp-hybridized carbons are involved in linear geometry with 180° bond angles, typically in triple bonds or cumulated double bonds.
Updated On: Jun 26, 2026
- I, II, III only
- II, III, IV only
- III, IV, V only
- I, III, IV only
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Recall sp-hybridization criteria.
A carbon atom is sp-hybridized if it is involved in a triple bond or in two double bonds (cumulene).
Step 2: Analyze each molecule.
- I. Ethane nitrile (CH\(_3\)CN): The carbon in the -CN group is sp-hybridized (triple bond).
- II. Buta-1,3-diene: Carbons are sp\(^2\)-hybridized (double bonds).
- III. Propa-1,2-diene (allene): The central carbon is sp-hybridized (two double bonds).
- IV. Ethyne (C\(_2\)H\(_2\)): Both carbons are sp-hybridized (triple bond).
- V. Benzene: Carbons are sp\(^2\)-hybridized.
Step 3: Identify molecules with sp carbons.
Molecules with sp carbons are I, III, and IV.
Step 4: Match with options.
Option (4) corresponds to I, III, IV only.
Step 5: Conclusion.
\[ \boxed{\text{I, III, IV only}} \]
A carbon atom is sp-hybridized if it is involved in a triple bond or in two double bonds (cumulene).
Step 2: Analyze each molecule.
- I. Ethane nitrile (CH\(_3\)CN): The carbon in the -CN group is sp-hybridized (triple bond).
- II. Buta-1,3-diene: Carbons are sp\(^2\)-hybridized (double bonds).
- III. Propa-1,2-diene (allene): The central carbon is sp-hybridized (two double bonds).
- IV. Ethyne (C\(_2\)H\(_2\)): Both carbons are sp-hybridized (triple bond).
- V. Benzene: Carbons are sp\(^2\)-hybridized.
Step 3: Identify molecules with sp carbons.
Molecules with sp carbons are I, III, and IV.
Step 4: Match with options.
Option (4) corresponds to I, III, IV only.
Step 5: Conclusion.
\[ \boxed{\text{I, III, IV only}} \]
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