Question:
What is the hybridization of the central atom in \(NH_3\)?
What is the hybridization of the central atom in \(NH_3\)?
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To determine hybridization, calculate the steric number (bonds + lone pairs): 2 = sp, 3 = sp^2, 4 = sp^3.
Updated On: Mar 18, 2026
- sp
- sp^2
- sp^3
sp^3d
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The Correct Option is C
Solution and Explanation
In \(NH_3\), the central atom is nitrogen. Nitrogen has 5 valence electrons and forms 3 single bonds with hydrogen atoms, leaving 1 lone pair. The steric number (number of bonded atoms + lone pairs) is: \[ 3 \, (\text{bonds}) + 1 \, (\text{lone pair}) = 4 \] A steric number of 4 corresponds to \(sp^3\) hybridization. Thus, the hybridization of nitrogen in \(NH_3\) is: \(\text{sp}^3\)
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