Step 1: First step – Nitration of benzene.
Benzene reacts with conc. HNO\(_3\)/conc. H\(_2\)SO\(_4\) at 323–333 K to form nitrobenzene:
\[
C_6H_6 \rightarrow C_6H_5NO_2
\]
Nitro group is a strong deactivating and meta-directing group.
Step 2: Second step – Chlorination.
Chlorination with Cl\(_2\)/AlCl\(_3\) occurs on nitrobenzene. Since –NO\(_2\) is meta-directing, chlorine enters the meta position:
m-chloronitrobenzene is formed
Step 3: Third step – Reduction.
H\(_2\)/Pd-C reduces –NO\(_2\) group to –NH\(_2\):
\[
C_6H_4ClNO_2 \rightarrow C_6H_4ClNH_2
\]
This gives chloroaniline.
Step 4: Directing effect after reduction.
–NH\(_2\) is a strong ortho/para directing group. Therefore, substitution pattern leads mainly to ortho/para chloroaniline, with ortho product being significant due to reaction conditions.
Step 5: Identify major product.
Considering activation after reduction and stability, the major product corresponds to ortho-chloroaniline type structure.
Step 6: Final conclusion.
\[
\boxed{\text{o-chloroaniline (major product)}}
\]