Question:
Identify the major product of the following reaction:
Identify the major product of the following reaction:
Show Hint
Hofmann bromamide degradation converts a primary amide into a primary amine containing one carbon atom less:
\[
RCONH_2 \xrightarrow{Br_2+NaOH} RNH_2
\]
Updated On: Jun 22, 2026
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The Correct Option is D
Solution and Explanation
Step 1: Identify the reactant.
The given reactant is \[ C_6H_5CONH_2 \] This compound is called benzamide. It is an aromatic primary amide.
Step 2: Identify the reagent.
The reagent used is \[ Br_2+NaOH \] This reagent is used in Hofmann bromamide degradation reaction.
Step 3: Apply Hofmann bromamide reaction.
In Hofmann bromamide degradation, a primary amide is converted into a primary amine with one carbon atom less.
The general reaction is \[ RCONH_2 \xrightarrow{Br_2+NaOH} RNH_2 \] Here, \[ R=C_6H_5 \] So, \[ C_6H_5CONH_2 \xrightarrow{Br_2+NaOH} C_6H_5NH_2 \]
Step 4: Understand the carbon loss.
In benzamide, the carbonyl carbon of the \(-CONH_2\) group is removed during the reaction as carbonate.
Therefore, benzamide gives aniline as the final product.
\[ C_6H_5CONH_2 \rightarrow C_6H_5NH_2 \]
Step 5: Final conclusion.
Hence, the major product is \[ \boxed{C_6H_5NH_2} \] which is aniline.
The given reactant is \[ C_6H_5CONH_2 \] This compound is called benzamide. It is an aromatic primary amide.
Step 2: Identify the reagent.
The reagent used is \[ Br_2+NaOH \] This reagent is used in Hofmann bromamide degradation reaction.
Step 3: Apply Hofmann bromamide reaction.
In Hofmann bromamide degradation, a primary amide is converted into a primary amine with one carbon atom less.
The general reaction is \[ RCONH_2 \xrightarrow{Br_2+NaOH} RNH_2 \] Here, \[ R=C_6H_5 \] So, \[ C_6H_5CONH_2 \xrightarrow{Br_2+NaOH} C_6H_5NH_2 \]
Step 4: Understand the carbon loss.
In benzamide, the carbonyl carbon of the \(-CONH_2\) group is removed during the reaction as carbonate.
Therefore, benzamide gives aniline as the final product.
\[ C_6H_5CONH_2 \rightarrow C_6H_5NH_2 \]
Step 5: Final conclusion.
Hence, the major product is \[ \boxed{C_6H_5NH_2} \] which is aniline.
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