Question:
Identify the major product formed from the following reaction:
Identify the major product formed from the following reaction:
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Grignard + alcohol gives alkane by protonation of carbanion; do not confuse with reaction with carbonyls which gives alcohol.
Updated On: Jul 18, 2026
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The Correct Option is A
Solution and Explanation
Step 1: Formation of Grignard reagent.
The alkyl halide reacts with Mg in dry ether to form Grignard reagent: \[ R–Br + Mg \xrightarrow{\text{ether}} R–MgBr \]
Step 2: React Grignard with alcohol.
Grignard reagents react with alcohols to form alkanes: \[ R–MgBr + CH_3OH \rightarrow R–H + CH_3OMgBr \]
Step 3: Mechanism overview.
The acidic proton of CH\(_3\)OH protonates the carbanion of R–MgBr to yield R–H.
Step 4: Identify the product.
The major product is the hydrocarbon corresponding to R, here represented as R–CH\(_3\) after methyl group from CH\(_3\)OH.
Step 5: Verify alternative products.
R–OH is not formed because Grignard reacts with alcohol to give alkane, not alcohol. Other options involve different functional groups.
Step 6: Final conclusion.
\[ \boxed{R–CH_3} \]
The alkyl halide reacts with Mg in dry ether to form Grignard reagent: \[ R–Br + Mg \xrightarrow{\text{ether}} R–MgBr \]
Step 2: React Grignard with alcohol.
Grignard reagents react with alcohols to form alkanes: \[ R–MgBr + CH_3OH \rightarrow R–H + CH_3OMgBr \]
Step 3: Mechanism overview.
The acidic proton of CH\(_3\)OH protonates the carbanion of R–MgBr to yield R–H.
Step 4: Identify the product.
The major product is the hydrocarbon corresponding to R, here represented as R–CH\(_3\) after methyl group from CH\(_3\)OH.
Step 5: Verify alternative products.
R–OH is not formed because Grignard reacts with alcohol to give alkane, not alcohol. Other options involve different functional groups.
Step 6: Final conclusion.
\[ \boxed{R–CH_3} \]
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