
The first transformation is the conversion of \(\ce{CH3-CH2-CH(Br)-CH2-F}\) to \(\ce{CH3-CH2-CH(Br)-CH3}\). This indicates the fluorine atom is replaced by a methyl group, suggesting a nucleophilic substitution where F is replaced. Since fluoride is a poor leaving group, a reagent like SbF3 is used to facilitate this by forming a complex.
The next transformation is from bromoalkane to iodoalkane, which is a typical Finkelstein reaction:
\[ \ce{R-Br + NaI -> R-I + NaBr} \]
This reaction occurs in dry acetone to drive the equilibrium toward product formation because NaBr precipitates out.
What is the correct boiling point order of the following haloalkanes? \[ \text{i) 2-chloro 2-methylpropane} \quad \text{ii) 1-Cholobutane} \quad \text{iii) 2-Chlorobutane} \]
