Step 1: Method
Set the sum of oxidation numbers of all atoms equal to the charge on the species.
Step 2: Check (A) and (B)
In \(\text{MnO}_4^-\): \(x + 4(-2) = -1\), so \(x = +7\). In \([\text{Cr}(\text{CN})_6]^{3-}\): \(x + 6(-1) = -3\), so \(x = +3\).
Step 3: Check (C)
In \(\text{Cr}_2\text{O}_3\): \(2x + 3(-2) = 0\), so \(x = +3\).
Step 4: Check (D)
In \(\text{CrO}_2\text{Cl}_2\): \(x + 2(-2) + 2(-1) = 0\), so \(x = +6\). This is chromyl chloride, with chromium in the +6 state.
Final Answer:
Chromium is +6 in chromyl chloride. This is option (D).
\[ \boxed{\text{(D) }\text{CrO}_2\text{Cl}_2} \]