Step 1: Understanding the Concept
In Stock notation the oxidation number of the metal is written in Roman numerals in brackets after its name or symbol.
Step 2: Find the Oxidation State
In \(\text{MnO}_{2}\), oxygen is \(-2\) each, so \(x+2(-2)=0\) and \(x=+4\).
Step 3: Compare the options
Mn in \(+4\) state is written \(\text{Mn(IV)O}_{2}\), option (D).
Final Answer:
Manganese dioxide is written as Mn(IV)O2.
\[ \boxed{\text{(D) }\text{Mn(IV)O}_{2}} \]