Question:
What is oxidation number of oxygen in super oxide of a monovalent metal?
What is oxidation number of oxygen in super oxide of a monovalent metal?
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A monovalent metal superoxide has the formula MO2 with the superoxide ion O2 minus.
Updated On: Nov 12, 2026
- \(-2\)
- \(-1/2\)
- \(-1\)
- \(-1.5\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
The superoxide of a monovalent metal has the formula \(\text{MO}_2\), and contains the superoxide ion \(\text{O}_2^{-}\).
Step 2: Set up the equation
The charge on the ion is \(-1\) shared between two oxygen atoms: \(2x=-1\).
Step 3: Solve
\(x=-\dfrac{1}{2}\)
Step 4: Compare the options
The oxidation number of oxygen is \(-\dfrac{1}{2}\), option (B).
Final Answer:
The oxidation number of oxygen in a superoxide is minus one half. \[ \boxed{\text{(B) }-1/2} \]
The superoxide of a monovalent metal has the formula \(\text{MO}_2\), and contains the superoxide ion \(\text{O}_2^{-}\).
Step 2: Set up the equation
The charge on the ion is \(-1\) shared between two oxygen atoms: \(2x=-1\).
Step 3: Solve
\(x=-\dfrac{1}{2}\)
Step 4: Compare the options
The oxidation number of oxygen is \(-\dfrac{1}{2}\), option (B).
Final Answer:
The oxidation number of oxygen in a superoxide is minus one half. \[ \boxed{\text{(B) }-1/2} \]
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