Step 1: Understanding the Concept
The vector product \(\vec{A}\times\vec{B}\) has magnitude \(AB\sin\theta\).
It is zero only when \(\theta = 0^{\circ}\) or \(180^{\circ}\), that is, when the two vectors lie along the same line.
Step 2: Apply to the Given Vectors
\(\vec{B}\) is along the positive y-axis, so \(\vec{A}\) must also lie along the y-axis.
Step 3: Compare the options
Among the options, only \(5\hat{j}\) points along the y-axis.
The vectors \(5\hat{k}\), \(5\hat{i}\) and \(-5\hat{k}\) are perpendicular to \(\hat{j}\), so their cross products with \(\vec{B}\) are not zero.
Final Answer:
The vector \(\vec{A}\) could be \(5\hat{j}\), which is option (C).
\[ \boxed{\text{(C) }5\hat{j}} \]