Question

Identify \(P\) and \(Q\) respectively of the following reaction

• A. 1
• B. 2
• C. 3
• D. 4

Hint:

Any compound containing the methyl ketone group \[ RCOCH_3 \] gives a positive iodoform test with \(\mathrm{I_2/NaOH}\) or \(\mathrm{NaOI}\), producing \[ RCOO^-Na^+ \] and yellow crystals of \[ CHI_3. \]

Answer 1

The Correct Option is D

Step 1: Identify the functional group present.
The given compound is an \(\alpha,\beta\)-unsaturated methyl ketone. It contains the group \[ R-CO-CH_3 \] where \(R\) is the cyclohexene ring system.

Step 2: Recall the reaction of methyl ketones with sodium hypoiodite.
\[ \mathrm{NaOI} \] causes the

iodoform reaction.
All compounds containing the methyl ketone group \[ RCOCH_3 \] undergo cleavage to give \[ RCOO^-Na^+ \] and \[ CHI_3 \] (iodoform).

Step 3: Apply the iodoform reaction.
The reaction proceeds as \[ RCOCH_3 \xrightarrow{\mathrm{NaOI}} RCOO^-Na^+ + CHI_3 \] For the given substrate, \[ R= \text{cyclohexene ring} \] Therefore, \[ P= \text{sodium cyclohexenecarboxylate} \] and \[ Q=CHI_3 \]

Step 4: Identify the correct option.
Among the given options, the pair Sodium cyclohexenecarboxylate and \[ CHI_3 \] corresponds to option (4).

Step 5: Final conclusion.
Hence, \[ \boxed{ P=\text{Sodium cyclohexenecarboxylate}, \qquad Q=CHI_3 } \] Therefore, the correct option is \[ \boxed{(4)} \]