Question

In the following reaction sequence, A and B respectively are

• A. $\text{CH}_3\text{CHClCH}_3 / \text{AlCl}_3; O_2, H_2O^+$
• B. $\text{CH}_3\text{CHClCH}_3 / \text{AlCl}_3; KMnO_4, H^+$
• C. $\text{Cl}_2 / FeCl_3; H_2O^+$
• D. $\text{CH}_3\text{CHClCH}_3 / \text{AlCl}_3; CrO_3 - H_2SO_4$

Hint:

Friedel-Crafts reactions often require a Lewis acid catalyst like AlCl\(_3\), followed by oxidation with O\(_2\) to introduce functional groups such as hydroxyl.

Answer 1

The Correct Option is A

- The reaction involves an alkyl halide (chloropropane) with AlCl\(_3\), followed by treatment with oxygen and water, which is a typical setup for a Friedel-Crafts alkylation followed by oxidation to form a phenol derivative.
- Option (1) correctly represents the reagents needed to achieve the conversion.
Thus, the correct answer is (1).