Step 1: Understanding the Concept:
The charge on the complex ion is set by the counter ion outside the brackets.
Step 2: Detailed Explanation:
Sulfate is \(\text{SO}_4^{2-}\), so the complex ion \([\text{Co(NH}_3)_5\text{Br}]\) has charge \(+2\).
Let the oxidation state of Co be \(x\). \(\text{NH}_3\) is neutral (0), and \(\text{Br}^-\) contributes \(-1\).
\[ x + 5(0) + (-1) = +2 \Rightarrow x = +3 \]
So cobalt is in the +3 state.
Step 3: Final Answer:
Option (B), \(+3\).
Final Answer:
Co is +3 in the complex.
\[ \boxed{\text{(B) }+3} \]