Question:
Identify geometry of \([\text{Ni(Cl)}_{4}]^{2-}\).
Identify geometry of \([\text{Ni(Cl)}_{4}]^{2-}\).
Show Hint
Cl- is a weak field ligand, so Ni(II) uses sp3 hybridisation.
Updated On: Nov 12, 2026
- Square planar
- Tetrahedral
- Octahedral
- Trigonal bipyramidal
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
The geometry of a complex follows from the hybridisation of the central metal, which depends on the ligand field strength.
Step 2: Metal and ligands
In \([\text{NiCl}_{4}]^{2-}\), nickel is in the \(+2\) state: \(3d^{8}\).
\(\text{Cl}^{-}\) is a weak field ligand and does not pair the d electrons.
Step 3: Hybridisation
Four ligands with no pairing give \(sp^{3}\) hybridisation, hence a tetrahedral shape.
Final Answer:
The complex is tetrahedral. \[ \boxed{\text{(B) }\text{Tetrahedral}} \]
The geometry of a complex follows from the hybridisation of the central metal, which depends on the ligand field strength.
Step 2: Metal and ligands
In \([\text{NiCl}_{4}]^{2-}\), nickel is in the \(+2\) state: \(3d^{8}\).
\(\text{Cl}^{-}\) is a weak field ligand and does not pair the d electrons.
Step 3: Hybridisation
Four ligands with no pairing give \(sp^{3}\) hybridisation, hence a tetrahedral shape.
Final Answer:
The complex is tetrahedral. \[ \boxed{\text{(B) }\text{Tetrahedral}} \]
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