Question:
Identify Hinsberg's reagent from following.
Identify Hinsberg's reagent from following.
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It is a sulphonyl chloride of benzene.
Updated On: Oct 1, 2026
- benzene sulfonic acid
- benzene sulphonyl chloride
- p-toluene sulphonyl chloride
- chlorosulphuric acid
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Hinsberg's test separates primary, secondary and tertiary amines. It uses a sulphonyl chloride that reacts with the N-H bonds.
Step 2: Reagent:
Hinsberg's reagent is benzene sulphonyl chloride, \(C_6H_5SO_2Cl\). A primary amine forms a sulphonamide that dissolves in alkali. A secondary amine forms a sulphonamide that does not dissolve. A tertiary amine does not react.
Step 3: Check the options:
Benzene sulphonic acid has no leaving Cl. p-Toluene sulphonyl chloride is tosyl chloride, a different reagent. Chlorosulphuric acid is not used for this test. So the answer is (B).
Final Answer:
Hinsberg's reagent is benzene sulphonyl chloride. \[ \boxed{B:\ \text{Benzene sulphonyl chloride}} \]
Hinsberg's test separates primary, secondary and tertiary amines. It uses a sulphonyl chloride that reacts with the N-H bonds.
Step 2: Reagent:
Hinsberg's reagent is benzene sulphonyl chloride, \(C_6H_5SO_2Cl\). A primary amine forms a sulphonamide that dissolves in alkali. A secondary amine forms a sulphonamide that does not dissolve. A tertiary amine does not react.
Step 3: Check the options:
Benzene sulphonic acid has no leaving Cl. p-Toluene sulphonyl chloride is tosyl chloride, a different reagent. Chlorosulphuric acid is not used for this test. So the answer is (B).
Final Answer:
Hinsberg's reagent is benzene sulphonyl chloride. \[ \boxed{B:\ \text{Benzene sulphonyl chloride}} \]
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