Step 1: Understanding the Concept:
The spectrochemical series arranges ligands by crystal field splitting power: \(\text{I}^- < \text{Br}^- < \text{Cl}^- < \text{F}^- < \text{OH}^- < \text{H}_2\text{O} < \text{NH}_3 < \text{en} < \text{CN}^-\).
Step 2: Compare:
Of the four ligands given, bromide is at the weak end, \(\text{OH}^-\) comes after the halides, \(\text{H}_2\text{O}\) is stronger and en is stronger still. So \(\text{Br}^-\) has the lowest field strength.
Final Answer:
Bromide is the weakest field ligand here, option (A).
\[ \boxed{\text{Br}^-} \]