Question:
Identify the geometry of the \([\text{CoF}_{6}]^{3-}\) complex ion.
Identify the geometry of the \([\text{CoF}_{6}]^{3-}\) complex ion.
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A complex with coordination number 6 is octahedral.
Updated On: Nov 12, 2026
- Triagonal bipyramidal
- Tetrahedral
- Octahedral
- Square planar
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
The geometry of a complex depends on its coordination number and hybridisation.
Step 2: Find the coordination number
In \([\text{CoF}_6]^{3-}\) six fluoride ligands are attached to \(\text{Co}^{3+}\), so the coordination number is 6.
Step 3: Hybridisation and shape
Fluoride is a weak field ligand, so the complex uses \(sp^3d^2\) hybridisation (outer orbital complex). Six bond pairs around the metal give an octahedral shape.
Final Answer:
The complex ion has octahedral geometry. \[ \boxed{\text{(C) }\text{Octahedral}} \]
The geometry of a complex depends on its coordination number and hybridisation.
Step 2: Find the coordination number
In \([\text{CoF}_6]^{3-}\) six fluoride ligands are attached to \(\text{Co}^{3+}\), so the coordination number is 6.
Step 3: Hybridisation and shape
Fluoride is a weak field ligand, so the complex uses \(sp^3d^2\) hybridisation (outer orbital complex). Six bond pairs around the metal give an octahedral shape.
Final Answer:
The complex ion has octahedral geometry. \[ \boxed{\text{(C) }\text{Octahedral}} \]
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