Concept:
$NaBH_4$ is a mild reducing agent that:
• Reduces aldehydes and ketones to alcohols
• Does not reduce esters under normal conditions
Step 1: Identify functional groups.
The given compound contains:
• One ketone group ($-CO-$)
• One ester group ($-COOCH_3$)
Step 2: Apply action of $NaBH_4$.
• Ketone $\rightarrow$ Secondary alcohol
• Ester $\rightarrow$ No reaction
Step 3: Write product.
\[
CH_3-CO-CH_2-COOCH_3 \rightarrow CH_3-CH(OH)-CH_2-COOCH_3
\]
Step 4: Final conclusion.
Thus, the correct product is:
\[
CH_3-CH(OH)-CH_2-COOCH_3
\]