Question:

Identify A in the following reaction:

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$NaBH_4$: - Reduces aldehydes & ketones - Does NOT reduce esters (use $LiAlH_4$ for that)
Updated On: May 13, 2026
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The Correct Option is A

Solution and Explanation

Concept: $NaBH_4$ is a mild reducing agent that:
• Reduces aldehydes and ketones to alcohols
• Does not reduce esters under normal conditions

Step 1:
Identify functional groups.
The given compound contains:
• One ketone group ($-CO-$)
• One ester group ($-COOCH_3$)

Step 2:
Apply action of $NaBH_4$.

• Ketone $\rightarrow$ Secondary alcohol
• Ester $\rightarrow$ No reaction

Step 3:
Write product.
\[ CH_3-CO-CH_2-COOCH_3 \rightarrow CH_3-CH(OH)-CH_2-COOCH_3 \]

Step 4:
Final conclusion.
Thus, the correct product is: \[ CH_3-CH(OH)-CH_2-COOCH_3 \]
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