Question

Formation of polyethylene from calcium carbide takes place as follows: CaC₂ + 2H₂O → Ca(OH)₂ + C₂H₂ C₂H₂ + H₂ → C₂H₄ nC₂H₄ → (–CH₂–CH₂–)ₙ The amount of polyethylene obtained from 64.1kg of CaC₂ is:

• A. \(7\,\text{kg}\)
• B. \(14\,\text{kg}\)
• C. \(21\,\text{kg}\)
• D. 28kg

Hint:

In polymer problems: Mass of polymer = mass of monomer formed Degree of polymerisation does not change total mass.

Answer 1

The Correct Option is D

Step 1: Molar mass of CaC₂=64g/mol 64.1kg ≈ 1000mol
Step 2: From reactions: 1mol CaC₂ → 1mol C₂H₄
Step 3: Molar mass of C₂H₄=28g/mol 1000 × 28 = 28000g = 28kg