Question

Formation of polyethylene from calcium carbide takes place as follows: beginaligned CaC₂ + 2H₂O &→ Ca(OH)₂ + C₂H₂
C₂H₂ + H₂ &→ C₂H₄
nC₂H₄ &→ (-CH₂-CH₂-)ₙ endaligned The amount of polyethylene obtained from 64.1kg of CaC₂ is:

• A. \(7\,\text{kg}\)
• B. \(14\,\text{kg}\)
• C. \(21\,\text{kg}\)
• D. 28kg

Hint:

In addition polymerisation, mass of polymer equals mass of monomer.

Answer 1

The Correct Option is D

Step 1: Molar mass of CaC₂=64g.
Step 2: 64g CaC₂ → 26g C₂H₂ → 28g C₂H₄.
Step 3: Hence 64.1kg CaC₂ → 28kg polyethylene.