Question:
For the four sets of three measured physical quantities as given below. Which of the following options is correct ?
(i) \(A_1 = 24.36,\ B_1 = 0.0724,\ C_1 = 256.2\)
(ii) \(A_2 = 24.44,\ B_2 = 16.082,\ C_2 = 240.2\)
(iii) \(A_3 = 25.2,\ B_3 = 19.2812,\ C_3 = 236.183\)
(iv) \(A_4 = 25,\ B_4 = 236.191,\ C_4 = 19.5\)
For the four sets of three measured physical quantities as given below. Which of the following options is correct ?
(i) \(A_1 = 24.36,\ B_1 = 0.0724,\ C_1 = 256.2\)
(ii) \(A_2 = 24.44,\ B_2 = 16.082,\ C_2 = 240.2\)
(iii) \(A_3 = 25.2,\ B_3 = 19.2812,\ C_3 = 236.183\)
(iv) \(A_4 = 25,\ B_4 = 236.191,\ C_4 = 19.5\)
(i) \(A_1 = 24.36,\ B_1 = 0.0724,\ C_1 = 256.2\)
(ii) \(A_2 = 24.44,\ B_2 = 16.082,\ C_2 = 240.2\)
(iii) \(A_3 = 25.2,\ B_3 = 19.2812,\ C_3 = 236.183\)
(iv) \(A_4 = 25,\ B_4 = 236.191,\ C_4 = 19.5\)
Show Hint
When quantities are added, the result is rounded to the least number of decimal places present among the terms. Add each set and round accordingly.
Updated On: Nov 5, 2026
- \(A_1 + B_1 + C_1 = A_2 + B_2 + C_2 = A_3 + B_3 + C_3 = A_4 + B_4 + C_4\)
- \(A_4 + B_4 + C_4 \lt A_1 + B_1 + C_1 \lt A_3 + B_3 + C_3 \lt A_2 + B_2 + C_2\)
- \(A_4 + B_4 + C_4 \lt A_1 + B_1 + C_1 = A_2 + B_2 + C_2 = A_3 + B_3 + C_3\)
- \(A_4 + B_4 + C_4 \gt A_3 + B_3 + C_3 = A_2 + B_2 + C_2 \gt A_1 + B_1 + C_1\)
Show Solution
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The Correct Option is D
Solution and Explanation
Rule: in addition, the final result keeps only as many decimal places as the term with the fewest decimal places.
(i) \(24.36 + 0.0724 + 256.2 = 280.6324\). Least decimal places = 1 (from 256.2), so the sum is \(280.6\).
(ii) \(24.44 + 16.082 + 240.2 = 280.722\). Least decimal places = 1, so the sum is \(280.7\).
(iii) \(25.2 + 19.2812 + 236.183 = 280.6642\). Least decimal places = 1 (from 25.2), so the sum is \(280.7\).
(iv) \(25 + 236.191 + 19.5 = 280.691\). Least decimal places = 0 (from 25), so the sum is \(281\).
Hence \(A_4 + B_4 + C_4\ (281) \gt A_3 + B_3 + C_3 = A_2 + B_2 + C_2\ (280.7) \gt A_1 + B_1 + C_1\ (280.6)\).
Answer: (4) \(A_4 + B_4 + C_4 \gt A_3 + B_3 + C_3 = A_2 + B_2 + C_2 \gt A_1 + B_1 + C_1\)
(i) \(24.36 + 0.0724 + 256.2 = 280.6324\). Least decimal places = 1 (from 256.2), so the sum is \(280.6\).
(ii) \(24.44 + 16.082 + 240.2 = 280.722\). Least decimal places = 1, so the sum is \(280.7\).
(iii) \(25.2 + 19.2812 + 236.183 = 280.6642\). Least decimal places = 1 (from 25.2), so the sum is \(280.7\).
(iv) \(25 + 236.191 + 19.5 = 280.691\). Least decimal places = 0 (from 25), so the sum is \(281\).
Hence \(A_4 + B_4 + C_4\ (281) \gt A_3 + B_3 + C_3 = A_2 + B_2 + C_2\ (280.7) \gt A_1 + B_1 + C_1\ (280.6)\).
Answer: (4) \(A_4 + B_4 + C_4 \gt A_3 + B_3 + C_3 = A_2 + B_2 + C_2 \gt A_1 + B_1 + C_1\)
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