Find the vector equation of the plane passing through the intersection of the planes
\(\overrightarrow r.(2\hat i+2\hat j-3\hat k)=7\),\(\overrightarrow r.(2\hat i+5\hat j+3\hat k)=9\) and through the point ( 2, 1, 3 ).
The equations of the planes are \(\overrightarrow r.(2\hat i+2\hat j-3\hat k)=7\) and \(\overrightarrow r.(2\hat i+5\hat j+3\hat k)=9\)
\(\Rightarrow \overrightarrow r.(2\hat i+2\hat j-3\hat k)-7=0\)...(1)
\(\Rightarrow\overrightarrow r.(2\hat i+5\hat j+3\hat k)-9=0\)...(2)
The equation of any plane through the intersection of the planes given in equation (1) and (2) is given by,
[ \(\overrightarrow r.(2\hat i+2\hat j-3\hat k)=7\) ]+\(\lambda\) [ \(\overrightarrow r.(2\hat i+5\hat j+3\hat k)=9\) ]=0, where \(\lambda\in\) R
\(\overrightarrow r.[(2\hat i+2\hat j-3\hat k)\)+\(\lambda(2\hat i+5\hat j+3\hat k)]=9\lambda+7\)
\(\overrightarrow r[(2+2\lambda)\hat i+(2+5\lambda)\hat j+(3\lambda-3)\hat k]=9\lambda+7\) ...(3)
The plane passes through the point (2,1, 3).
Therefore, its position vector is given by, \(\overrightarrow r.2\hat i+2\hat j+3\hat k\)
Substituting in equation (3), we obtain
\((2\hat i+2\hat j-3\hat k).\)\([(2+2\lambda)\hat i+(2+5\lambda)\hat j+(3\lambda-3)\hat k]=9\lambda+7\)
\(\Rightarrow[(2+2\lambda)+(2+5\lambda)+(3\lambda-3)]=9\lambda+7\)
\(\Rightarrow\) 18λ-3=9λ+7
\(\Rightarrow\) 9λ=10
\(\Rightarrow\) λ=\(\frac{10}{9}\)
Substituting \(\lambda=\frac{10}{9}\) in equation(3), we obtain
\(\overrightarrow r\bigg(\frac{38}{9}\hat i+\frac{68}{9}\hat j+\frac{3}{9}\hat k\bigg)=17\)
\(\Rightarrow \overrightarrow r (38\hat i+68\hat j+3\hat k)=153\)
This is the vector equation of the required plane.
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Find the shortest distance between the lines \(\frac{x+1}{7}=\frac{y+1}{-6}=\frac{z+1}{1}\) and \(\frac{x-3}{1}=\frac{y-5}{-2}=\frac{z-7}{1}\)
Find the shortest distance between the lines whose vector equations are
\(\overrightarrow r=(\hat i+2\hat j+3\hat k)+\lambda(\hat i-3\hat j+2\hat k)\)
and \(\overrightarrow r=(4\hat i+5\hat j+6\hat k)+\mu(2\hat i+3\hat j+\hat k)\)
Find the shortest distance between the lines whose vector equations are
\(\overrightarrow r=(1-t)\hat i+(t-2)\hat j+(3-2t)\hat k\) and
\(\overrightarrow r=(s+1)\hat i+(2s-1)\hat j-(2s+1)\hat k\)
In the following cases, find the distance of each of the given points from the corresponding given plane.
Point Plane
(a) (0,0,0) 3x-4y+12z=3
(b) (3,-2,1) 2x-y+2z+3=0
(c) (2,3,-5) x+2y-2z=9
(d) (-6,0,0) 2x-3y+6z-2=0
determine whether the given planes are parallel or perpendicular,and in case they are neither, find the angles between them. (a)7x+5y+6z+30=0 and 3x-y-10z+4=0
(b)2x+y+3z-2=0 and x-2y+5=0
(c)2x-2y+4z+5=0 and 3x-3y+6z-1=0
(d)2x-y+3z-1=0 and 2x-y+3z+3=0
(e)4x+8y+z-8=0 and y+z-4=0
A surface comprising all the straight lines that join any two points lying on it is called a plane in geometry. A plane is defined through any of the following uniquely: