Find the equation of the planes that passes through three points.
(a) (1,1,-1),(6,4,-5),(-4,-2,-3)
(b) (1,1,0),(1,2,1),(-2,2,-1).
(a)The given points are A (1,1,-1), B (6,4,-5), and C (-4,-2,3).
\(\begin{vmatrix}1&1&-1\\6&4&-5\\-4&-2&3\end{vmatrix}\)=(12-10)-(18-20)-(-12+16)
=2+2-4 =0
Since, A, B, C are collinear points, there will be infinite number of planes passing through the given points.
(b)The given points are A (1,1,0), B (1,2,1), and C (-2,2,-1).
\(\begin{vmatrix}1&1&0\\1&2&1\\-2&-2&1\end{vmatrix}\)=(-2-2)-(2+2)
=-8≠0
Therefore, a plane will pass through the points A, B, and C.
It is known that the equation of the plane through the points, (x1,y1,z1), (x2,y2,z2), and (x3,y3,z3), is
\(\begin{vmatrix}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{vmatrix}\)=0
\(\Rightarrow \begin{vmatrix}x-1&y-1&z\\0&1&1\\-3&1&-1\end{vmatrix}\)=0
\(\Rightarrow\) (-2)(x-1)-3(y-1)+3z=0
\(\Rightarrow\)-2x-3y+3z+2+3=0
\(\Rightarrow\)- 2x-3y+3z=-5
\(\Rightarrow\) 2x+3y-3z=5
This is the cartesian equation of the required plane.
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).
A surface comprising all the straight lines that join any two points lying on it is called a plane in geometry. A plane is defined through any of the following uniquely: