Question

Find the angle of deviation produced by the prism.

Answer 1

Deviation Produced by the Prism

The deviation produced by the prism depends on the refractive index, the angle of the prism, and the angle of incidence. The total deviation \( \delta \) can be calculated using the following relation:

\[ \delta = (\theta_1 + \theta_2) - \text{Prism angle} \]

Where:

• \( \theta_1 \) is the angle of incidence at the first surface (which is \( 0^\circ \) as the light is incident normally)
• \( \theta_2 \) is the angle of refraction inside the prism

Since the refractive index is \( \sqrt{2} \) and the light is passing through a right-angled prism, the angle of deviation can be computed by:

\[ \delta = 60^\circ \]

Thus, the angle of deviation produced by the prism is: \( \delta = 60^\circ \)