Find the angle between the planes whose vector equations are
\(\overrightarrow r.(2\hat i+2\hat j-3\hat k)=5\) and \(\overrightarrow r.(3\hat i-3\hat j+5\hat k)=3\)
The equations of the given planes are \(\overrightarrow r.(2\hat i+2\hat j-3\hat k)=5\) and \(\overrightarrow r.(3\hat i-3\hat j+5\hat k)=3\)
It is known that if \(\overrightarrow n_1\) and \(\overrightarrow n_2\) are normal to the planes, \(\overrightarrow r.\overrightarrow n_1=\overrightarrow d_1\) and \(\overrightarrow r.\overrightarrow n_2=\overrightarrow d_2\)
then the angle between them, Q, is given by,
cos Q= \(\begin{vmatrix}\frac{\overrightarrow n_1.\overrightarrow n_2}{\|\overrightarrow n_1\| \overrightarrow n_2 \|}\end{vmatrix}\)...(1)
Here, \(\overrightarrow n_1=2\hat i+2\hat j-3\hat k\) and \(\overrightarrow n_2=3\hat i-3\hat j+5\hat k\)
∴ \(\overrightarrow n_1.\overrightarrow n_2\)= \((2\hat i+2\hat j-3\hat k)\)\((3\hat i-3\hat j+5\hat k)\)
=2.3+2.(-3)+(-3).5 =-15
|\(\overrightarrow n_1\)|=\(\sqrt{(2)^2+(2)^2+(-3)^2}=\sqrt{17}\)
|\(\overrightarrow n_2\)|=\(\sqrt{(3)^2+(-3)^2+(5)^2}=\sqrt{43}\)
Substituting the value of \(\overrightarrow n_1.\overrightarrow n_2\),|\(\overrightarrow n_1\)|and|\(\overrightarrow n_2\)| in equation(1), we obtain
cos Q=|\(\frac{-15}{\sqrt{17}.\sqrt{43}}\)|
\(\Rightarrow\) cos Q=\(\frac{15}{\sqrt{731}}\)
\(\Rightarrow\) cos Q-1 =\(\bigg(\frac{15}{\sqrt{731}}\bigg)\)
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Find the shortest distance between the lines \(\frac{x+1}{7}=\frac{y+1}{-6}=\frac{z+1}{1}\) and \(\frac{x-3}{1}=\frac{y-5}{-2}=\frac{z-7}{1}\)
Find the shortest distance between the lines whose vector equations are
\(\overrightarrow r=(\hat i+2\hat j+3\hat k)+\lambda(\hat i-3\hat j+2\hat k)\)
and \(\overrightarrow r=(4\hat i+5\hat j+6\hat k)+\mu(2\hat i+3\hat j+\hat k)\)
Find the shortest distance between the lines whose vector equations are
\(\overrightarrow r=(1-t)\hat i+(t-2)\hat j+(3-2t)\hat k\) and
\(\overrightarrow r=(s+1)\hat i+(2s-1)\hat j-(2s+1)\hat k\)
In the following cases, find the distance of each of the given points from the corresponding given plane.
Point Plane
(a) (0,0,0) 3x-4y+12z=3
(b) (3,-2,1) 2x-y+2z+3=0
(c) (2,3,-5) x+2y-2z=9
(d) (-6,0,0) 2x-3y+6z-2=0
determine whether the given planes are parallel or perpendicular,and in case they are neither, find the angles between them. (a)7x+5y+6z+30=0 and 3x-y-10z+4=0
(b)2x+y+3z-2=0 and x-2y+5=0
(c)2x-2y+4z+5=0 and 3x-3y+6z-1=0
(d)2x-y+3z-1=0 and 2x-y+3z+3=0
(e)4x+8y+z-8=0 and y+z-4=0
A plane is demarcated as two-dimensional in nature and the one which has a flat surface that prolongs infinitely far in two dimensions. It is set up by some stack of lines that are kept together.
Angles between two planes refer to the acute angle which is manifest by the standard vectors of the planes. If the standard vectors of two planes are rectangular, then we can say they are perpendicular. This specific portion tells us what a plane is and what is the angle between the two planes, it also shows us how to calculate the angles between the two planes in a Cartesian plane.