1. Magnetic Moment of a Current-Carrying Coil:
The magnetic moment (\( \mu \)) of a current-carrying coil is a vector quantity that represents the strength and orientation of the coil's magnetic field. It is defined as the product of the current \( I \) flowing through the coil and the area \( A \) of the coil, along with the direction normal to the plane of the coil (perpendicular to the coil's surface).
The formula for the magnetic moment of a coil is given by:
\[ \mu = I \cdot A \]
Where:
2. Direction of Magnetic Moment:
The direction of the magnetic moment vector is determined by the right-hand rule. If the fingers of the right hand curl in the direction of the current, then the thumb points in the direction of the magnetic moment.
3. SI Unit of Magnetic Moment:
The SI unit of magnetic moment is the ampere-square meter (A·m²), which is derived from the current \( I \) in amperes and the area \( A \) in square meters.
4. Conclusion:
A short bar magnet placed with its axis at 30º with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 × 10-2 J. What is the magnitude of magnetic moment of the magnet?
A short bar magnet of magnetic moment m = 0.32 J T-1 is placed in a uniform magnetic field of 0.15 T. If the bar is free to rotate in the plane of the field, which orientation would correspond to its ( a ) stable, and ( b) unstable equilibrium? What is the potential energy of the magnet in each case?
A closely wound solenoid of 800 turns and area of cross section 2.5 × 10-4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?