Question:
Consider the reaction of Cumene: (i) $O_{2}$ (ii) $H_{3}O^{+} \rightarrow A + B$. A is acidic and forms a salt with NaOH. X and Y are reagents to convert A and B to hydrocarbons. What are X and Y?
Consider the reaction of Cumene: (i) $O_{2}$ (ii) $H_{3}O^{+} \rightarrow A + B$. A is acidic and forms a salt with NaOH. X and Y are reagents to convert A and B to hydrocarbons. What are X and Y?
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Clemmensen reduction turns ketones into alkanes.
Updated On: Oct 15, 2026
- $X=Zn; Y=NaBH_{4}$
- $X=NaBH_{4}; Y=Zn, \Delta$
- $X=Zn; Y=Zn(Hg), HCl$
- $X=Zn(Hg), HCl; Y=Zn$
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The Correct Option is C
Solution and Explanation
Step 1: Concept
This is the industrial method for producing phenol (A) and acetone (B) from cumene.
Step 2: Meaning
Phenol (A) can be reduced to benzene using Zinc dust. Acetone (B) can be reduced to propane using Clemmensen reduction ($Zn(Hg), HCl$).
Step 3: Analysis
To convert A (Phenol) to benzene, we use $Zn$. To convert B (Acetone) to propane, we use $Zn(Hg), HCl$.
Step 4: Conclusion
X is $Zn$ and Y is $Zn(Hg), HCl$.
Final Answer: (C)
This is the industrial method for producing phenol (A) and acetone (B) from cumene.
Step 2: Meaning
Phenol (A) can be reduced to benzene using Zinc dust. Acetone (B) can be reduced to propane using Clemmensen reduction ($Zn(Hg), HCl$).
Step 3: Analysis
To convert A (Phenol) to benzene, we use $Zn$. To convert B (Acetone) to propane, we use $Zn(Hg), HCl$.
Step 4: Conclusion
X is $Zn$ and Y is $Zn(Hg), HCl$.
Final Answer: (C)
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