The inductive reactance limits the current in a purely inductive circuit.
The average power supplied to an inductor over one complete cycle is zero.
The inductive reactance is directly proportional to the frequency of the emf.
The emf of the source and current oscillate symmetrically about zero value.
The current leads the voltage by \(\dfrac{\pi}{2}\).
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The Correct Option is
Solution and Explanation
In a pure inductive circuit, current lags the voltage by:
\[
\frac{\pi}{2}
\]
So statement (E), which says current leads the voltage, is wrong.
Hence,
\[
\boxed{(E)}
\]