Question:

An alternating current having the peak value \( 10\sqrt{2}\,\text{A} \) is used to heat a metal wire. To produce the same heating effect, the constant current required is

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Heating effect depends on RMS value.
Updated On: Apr 21, 2026
  • \(10\sqrt{2}\,\text{A} \)
  • \(5\,\text{A} \)
  • \(14\,\text{A} \)
  • \(7\,\text{A} \)
  • \(10\,\text{A} \)
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The Correct Option is

Solution and Explanation

Concept: \[ I_{rms} = \frac{I_0}{\sqrt{2}} \]

Step 1:
Compute RMS.
\[ I_{rms} = \frac{10\sqrt{2}}{\sqrt{2}} = 10\,\text{A} \]
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