Question:

Calculate the number of unit cells in 0.79 g metal if product of density and volume of unit cell is 1.58 $\times$ 10$^{-22}$ g.

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The mass of a unit cell is the product of its density and its volume.
Updated On: Apr 30, 2026
  • 3.96 $\times$ 10$^{21}$
  • 1.72 $\times$ 10$^{21}$
  • 4.46 $\times$ 10$^{21}$
  • 5.0 $\times$ 10$^{21}$
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The Correct Option is D

Solution and Explanation

Step 1: Concept
Mass of one unit cell = Density ($\rho$) $\times$ Volume of unit cell ($V$).
Given $\rho \times V = 1.58 \times 10^{-22}$ g.
Step 2: Formula
Number of unit cells = $\frac{\text{Total Mass}}{\text{Mass of one unit cell}}$.
Step 3: Calculation
$N = \frac{0.79}{1.58 \times 10^{-22}} = 0.5 \times 10^{22} = 5.0 \times 10^{21}$.
Step 4: Conclusion
The number of unit cells is 5.0 $\times$ 10$^{21}$.
Final Answer:(D)
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