Question

Calculate the amount of oxalic acid required to prepare 250 mL of 0.35 M solution of oxalic acid.

• A. 8.735 g
• B. 7.875 g
• C. 8.175 g
• D. 8.375 g

Hint:

First find the moles needed, then multiply by the molar mass of oxalic acid.

Answer 1

The Correct Option is B

Step 1: Moles required = Molarity x Volume in litres = \(0.35 \times 0.250 = 0.0875\) mol.

Step 2: Molar mass of oxalic acid, \(H_2C_2O_4\), is \(2(1) + 2(12) + 4(16) = 2 + 24 + 64 = 90\) g/mol.

Step 3: Mass required = moles x molar mass = \(0.0875 \times 90 = 7.875\) g. \[\boxed{7.875\ \text{g}}\]