Question:
Calcium carbide \(+\,D_2O \rightarrow X + Ca(OD)_2\). The hybridization of carbon atom/s in \(X\)
Calcium carbide \(+\,D_2O \rightarrow X + Ca(OD)_2\). The hybridization of carbon atom/s in \(X\)
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Carbon atoms involved in a triple bond always show
\[
sp
\]
hybridization and possess linear geometry with bond angle
\[
180^\circ
\]
Updated On: Jun 22, 2026
- \(sp^2\)
- \(sp\)
- \(sp^3\)
- \(dsp^2\)
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The Correct Option is B
Solution and Explanation
Step 1: Write the reaction of calcium carbide with heavy water.
Calcium carbide reacts with heavy water \((D_2O)\) to form deuterated acetylene and calcium hydroxide: \[ CaC_2+2D_2O\rightarrow C_2D_2+Ca(OD)_2 \] Thus, \[ X=C_2D_2 \] which is deuterated ethyne (acetylene).
Step 2: Write the structure of \(C_2D_2\).
The structure of ethyne is \[ D-C\equiv C-D \] There is a triple bond between the two carbon atoms.
Step 3: Determine the hybridization of carbon atoms.
Each carbon atom forms: \[ 1 \sigma \text{ bond with deuterium} \] and \[ 1 \sigma \text{ bond with another carbon} \] Thus, each carbon atom forms two sigma bonds and has linear geometry.
Therefore, each carbon atom undergoes \[ sp \] hybridization.
Step 4: Final conclusion.
Hence, the hybridization of carbon atoms in \(X\) is \[ \boxed{sp} \]
Calcium carbide reacts with heavy water \((D_2O)\) to form deuterated acetylene and calcium hydroxide: \[ CaC_2+2D_2O\rightarrow C_2D_2+Ca(OD)_2 \] Thus, \[ X=C_2D_2 \] which is deuterated ethyne (acetylene).
Step 2: Write the structure of \(C_2D_2\).
The structure of ethyne is \[ D-C\equiv C-D \] There is a triple bond between the two carbon atoms.
Step 3: Determine the hybridization of carbon atoms.
Each carbon atom forms: \[ 1 \sigma \text{ bond with deuterium} \] and \[ 1 \sigma \text{ bond with another carbon} \] Thus, each carbon atom forms two sigma bonds and has linear geometry.
Therefore, each carbon atom undergoes \[ sp \] hybridization.
Step 4: Final conclusion.
Hence, the hybridization of carbon atoms in \(X\) is \[ \boxed{sp} \]
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